1(x)=4x^2-3x

Solution for 1(x)=4x^2-3x equation:

1(x)=4x^2-3x

We move all terms to the left:

1(x)-(4x^2-3x)=0

We add all the numbers together, and all the variables

x-(4x^2-3x)=0

We get rid of parentheses

-4x^2+x+3x=0

We add all the numbers together, and all the variables

-4x^2+4x=0

a = -4; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-4)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-4}=\frac{-8}{-8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-4}=\frac{0}{-8}
=0
$